Java: Count the number of blank characters in a given string

The following code is going to print a message with the number of white spaces in a given sentence.



First, we need to write the name of the procedure: countWhiteSpaces

public static void countWhiteSpaces() {

}

The above procedure is static because only one copy of the object is needed.

Then, we need Scanner, in order for the user to be able to write the sentence on the screen. We will also print indications for the user.

Scanner kb = new Scanner(System.in);
System.out.println("Enter a sentence...");

The kb variable will hold the sentence the user is going to type. We store this information into the String called sentence.

String sentence = kb.nextLine();

We need to count the figure out the length of the sentence, for that we user the .lenght() property.

int senLen = sentence.length();

Also, a variable needs to be initialized for counting the number of white spaces.

int blankSpaces = 0;

In order to check and count the number of white spaces in a sentence we will use a for loop. This is going to start in 0 and will iterate until the length of the sentence. The if statement is going to check whether each character is an empty space or not, and then increase the blankSpace variable.

for (int i = 0; i < senLen; i++) {
     if (sentence.charAt(i) == ' ') {
            blankSpaces++;
     }
}

Finally, we are going to print the result

System.out.println("The number of white spaces in your sentence is: " + blankSpaces);

The final code is going to look like this:

import java.util.Scanner;

public class couSpaces {

public static void main(String[] args) {
// TODO Auto-generated method stub
countWhiteSpaces();
}

public static void countWhiteSpaces() {

Scanner kb = new Scanner(System.in);
System.out.println("Enter a sentence...");

String sentence = kb.nextLine();
int senLen = sentence.length();
int blankSpaces = 0;

for (int i = 0; i <  senLen; i++) {

if (sentence.charAt(i) == ' ') {
blankSpaces++;
}

}

System.out.println("The number of white spaces in your sentence is: " + blankSpaces);
}

}

Java: sum of the first N positive odd integer numbers

Write a fragment of code that will compute the sum of the first n positive
odd integers. For example, if n is 5, you should compute 1 +3 + 5 +7 + 9.

For doing so write the following code:


public static void sumNPositiveOddIntegers() {
 System.out.println("Escriba un numero entero...");
 Scanner kb = new Scanner(System.in);
 int n = kb.nextInt();

 int x = 1;
 int sum = 0;
 for (int i = 0; i < n; i++)
 {
  sum += x;
  x += 2;
  System.out.println(x);
 }
 System.out.println("The sum of first " + n + " positive odd integers is: " + sum);

}


Code explanation:

public static void sumNPositiveOddIntegers(): As we are printing the result we use void.

Scanner kb = new Scanner(System.in): Here we declare the variable kb with the method Scanner in order to read from the keyboard.

int n = kb.nextInt(): Assign to the variable n the integer value from the keyboard.

 int x = 1, sum = 0: Initialize the variables x and sum.

 for(int i = 0; i < n; i++): This loop initializes the variable I with value 0. Then it states: while i is less than n, then the i's variable value will be increasing.

sum += x: the variable sum will be storing the value of x during the loop.

x += 2: x will be increasing in pairs in order to sort the odd numbers. That's way we initialize it with value 1.

System.out.println(x): Prints out the x's value that will be the positive odd integer numbers.

Finally, the last line of code will print the sum of the previous numbers.