Java: sum of the first N positive odd integer numbers

Write a fragment of code that will compute the sum of the first n positive
odd integers. For example, if n is 5, you should compute 1 +3 + 5 +7 + 9.

For doing so write the following code:


public static void sumNPositiveOddIntegers() {
 System.out.println("Escriba un numero entero...");
 Scanner kb = new Scanner(System.in);
 int n = kb.nextInt();

 int x = 1;
 int sum = 0;
 for (int i = 0; i < n; i++)
 {
  sum += x;
  x += 2;
  System.out.println(x);
 }
 System.out.println("The sum of first " + n + " positive odd integers is: " + sum);

}


Code explanation:

public static void sumNPositiveOddIntegers(): As we are printing the result we use void.

Scanner kb = new Scanner(System.in): Here we declare the variable kb with the method Scanner in order to read from the keyboard.

int n = kb.nextInt(): Assign to the variable n the integer value from the keyboard.

 int x = 1, sum = 0: Initialize the variables x and sum.

 for(int i = 0; i < n; i++): This loop initializes the variable I with value 0. Then it states: while i is less than n, then the i's variable value will be increasing.

sum += x: the variable sum will be storing the value of x during the loop.

x += 2: x will be increasing in pairs in order to sort the odd numbers. That's way we initialize it with value 1.

System.out.println(x): Prints out the x's value that will be the positive odd integer numbers.

Finally, the last line of code will print the sum of the previous numbers.